Since P is given to be a partial order relation, options (i) & (ii) are ruled out as they violate antisymmetry which says that if (a,b)∊R & (b,a)∊R => a=b but 22 ≠101.
Now 145%10≤265%10 and the evaluating the second condition gives (0,0) which is given to be in P. In similar vein (iv) can also be checked to be in P.
Hence option iii & iv is correct.