Normalised eigen value is similar to unit vector. i.e. if $[x_1,x_2] = [a,b]$ is eigen vector then its normalized eigen vector will be
$=[a\div\sqrt{a_2+b_2}, b \div \sqrt{a_2+b_2}]$
= [ a/√(a2+b2),b/√(a2+b2)]
Hence find the eigen vector first and divide it with its magnitude like above to get normalized eigen vector.