Consider the $SDTS$ for the ambiguous grammar
$E \rightarrow E + E$ $out ("1 + 2 ")$
$E \rightarrow E ^{*} E$ $out ("2 ^{*} 3")$
$E \rightarrow num$ $out (num.val)$
Assume a shift reduce parser. The output is treated as an arithmetic expression in $C$ & evaluated. The input is $1 ^{*} 1 + 1$.
The value obtained is _______.
EDIT: Here's the explanation given..