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The number $(123456)_8$ is equivalent to

  1. $\text{(A72E)}_{16}$ and $(22130232)_4$
  2. $\text{(A72E)}_{16}$ and $(22131122)_4$
  3. $\text{(A73E)}_{16}$ and $(22130232)_4$
  4. $\text{(A62E)}_{16}$ and $(22120232)_4$
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2 Answers

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$(123456)_{8} = (001\; 010\;011\; 100\; 101\; 110)_{2} = (00\; \underbrace{1010}_{A}\; \underbrace{0111}_7\; \underbrace{0010}_2\; \underbrace{1110}_E)_{2} = \text{(A72E)}_{16}$
$= (00 \;10\; 10\; 01\; 11\; 00\; 10\; 11\; 10)_{2} = (22130232)_{4}$

So, option (A).
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as 8 =2$^3$ so 3 bits of binary are used to represent one unit of octal

so break each unit of (123456)$_8$ into its corresponding 3 bit binary number 

=  (001 010 011 100 101 110)$_2$

as 16=2$^4$ so 4 bits of binary are used to represent one unit in Hexadecimal 

club 4 bits of binary representation of given number from LSB and write corresponding Hexadecimal number.

=(00 1010 0111 0010 1110)$_2$ = (A72E)$_1$$_6$

 

as 4=2$^2$ so 2 bits of binary are used to represent one unit in 4 base number system

club 2 bits of binary representation of given number from LSB and write corresponding Hexadecimal number.

=(00 10 10 01 11 00 10 11 10)$_2$ = (22130232)$_4$

option (A)

Answer:

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