Empcode is unique, therefore it is the primary key. Since the primary key consists of a single attribute there will be no partial dependency, hence the relation is in 2NF.
From the question we get the FDs as below:
pincode -> city, state
street,city,state -> pincode
LHS of every FD is not super key and RHS is not prime attribute
From the FDs we can see that there are transitive dependencies, hence the table is not in 3NF.