Register

how many NAND gate required for AC+BD+AB

331 views
0 votes
0 votes
User Avatar

1 Answer

1 votes
1 votes
According to me it should be 4.

1 for (AC)'

1 for (BD)'

1 for (AB)'

then combine all into 1 Nand as ((AC)'.(BD)'.(AB)')'---->AC+BD+AB.
User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

3 votes
3 votes
1 answer
2
h4kr asked Jan 21, 2023
264 views
How many NAND gates required?
User Avatar
3 votes
3 votes
4 answers
3
Gobind asked Oct 11, 2014
3,469 views
Kindly have a try .... IN canonical POS form following equation is written as (ABC)=AB+BC+AC (A)πM(0,1,2,4) (B)πM(3,5,6,7) (A)πM(0,1,2,3) (A)πM(4,5,6,7)
Kindly have a try .... IN canonical POS form following equation is written asF(A,B,C)=AB+BC+AC (A)πM(0,1,2,4) (B)πM(3,5,6,7)(C)πM(0,1,2,3) (D)πM(4,5,6,7)
User Avatar
3 votes
3 votes
3 answers
4
NERU.91 asked Apr 29, 2015
8,358 views
NFA for the language, L= (ab, ba)* would have how many states?
User Avatar
Link Copied!