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Fill $f(x,y,z)=xy+x'z$ in K-map

Hazard occurred because a variable and its complement passed through different number of logic operations. 

In other words, if a variable and its complement are present in different product terms, may cause Hazards. 

Here it is variable $x$, that may cause Hazard. 

So make an extra pair in K-map that doesn't contain variable $x$.

so $f(x,y,z)=xy+x'z +yz$ is Hazard Free.

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