0 votes 0 votes A RAM chip has 32 rows and 16 columns each with a single bit. The number of address line input required to gain unique addressing to every location is __________ . CO and Architecture made-easy-test-series digital-logic ram + – khushtak asked Jan 28, 2016 edited Mar 5, 2019 by akash.dinkar12 khushtak 598 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply Arjun commented Jan 28, 2016 reply Follow Share out of syllabus for 2016. 1 votes 1 votes Rishabh Gupta 2 commented Oct 19, 2017 reply Follow Share @Arjun sir, even if it's not in the syllabus, but what should be the answer? I think only rows are accessed separately, which gives $2^5 = 32$ addresses, i.e. 5 address lines. This will give us a 32 x 16 bit RAM. Correct? 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes FOR UNIQUE ADDRESSING WE HAVE TO GIVE ONE INPUT TO EACH AND EVERY CHIP We have 2^5 ROWS AND 2^4 COLUMNS Hence we need 9:2^9 Decoder Hence Total no of Address Line required is 9. Ankesh Gautam answered Jan 29, 2016 Ankesh Gautam comment Share Follow See 1 comment See all 1 1 comment reply papesh commented Feb 29, 2016 reply Follow Share decoder is required only for rows not for columns i think so.... 0 votes 0 votes Please log in or register to add a comment.