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Consider the Boolean operator # with the following properties :

$x \# 0 = x, x \# 1=\overline{x}, x \# x = 0$ and $x \# \overline{x} = 1.$ Then $x\#y$ is equivalent to 

  1. $x\overline{y}+\overline{x}y$
  2. $x\overline{y}+ \overline{x} \; \overline{y}$
  3. $\overline{x}y+xy$
  4. $xy+\overline{x} \; \overline{y}$
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These are properties of XOR function.. so answer is A) $x \overline{y}+\overline{x}y$
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