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31 votes
31 votes

$A$ and $B$ are friends. They decide to meet between 1:00 pm and 2:00 pm on a given day. There is a condition that whoever arrives first will not wait for the other for more than $15$ minutes. The probability that they will meet on that day is

  1. $1/4$
  2. $1/16$
  3. $7/16$
  4. $9/16$
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8 Answers

1 votes
1 votes
Mark this formula for this kind of any question.

x=minutes one could not wait for.

n=60/x.

probability they meet= (2n-1)/n^2

 

here x=60/15 =4.

 

probabi;ity=8-1/16 =7/16
0 votes
0 votes
We can derive one formula also from graph For(n*n)

(n^2-(n-1)^2) /n^2

from given ques n=4

(16-9)/16

7/16 Final answer
Answer:

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