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If two teams A and B play a best-of-five series, and if team A has a 1/4 chance of winning any game (and team B has 3/4 chance of winning any game), then what is the expected number of games played in the series. (Note that in a best-of-five series, the teams play games until one team has won three games.)
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Please cope with my writing.

You need to calculate the answer approx. as I have given the equation in terms of p and q with p=1/4 (A's Chance of winning) and q=3/4 (B's chance of winning).

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