Question

What is the chance that a leap year selected at random will contain 52 Sundays?

Answer 1

total no of days in leap year is =366

so 366/7=52.29 which means 52 complete weaks so 52*7=364 days so last 2 days are remainingit can be

mon&tue ,  tue&wed,  wed&thur,  thur&fri,  fri&sat,  sat&sun ,  sun&mon  and we want

p(52 sunday)=all pair expect those having sunday bcz we want 52 sunday/TOTAL PAIR

so  ans is 5/7

Answer 2

with "contains 52 sundays" it means atleast 52 sundays.
every year (normal or leap year) contain 52 weeks therefore 52 sundays.
so probablity is 1.

Answer 3

@srestha --- Look this 

In a leap or non leap year you any ways have 52 week . so 52 week will cover will 52 sundays so prob 1 ;

In a non leap year it is ( 52*7 + 1) 

In a leap year it is (52*7 + 2) 

Bdw for the above answer : if they would have asked 53 sundays in a non leap year it would have been 2/7 

Comments

yes if 53 sundays then there must be 1 sunday in last 2 days

So, answer will be 2/7

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Yes you have choosen wrong answer as best one . Choose Arpit Tripathi answer that is right :)