7,602 views
7 votes
7 votes

What will be the efficiency of a Stop and Wait protocol, if the transmission time for a frame is $20$ns and the propagation time is $30$ns?

  1. $20$%
  2. $25$%
  3. $40$%
  4. $66$%

6 Answers

0 votes
0 votes
i think ans===25% option (B)correct

ɳ=1/1+2*a

where a=propagation delay/transmission delay
0 votes
0 votes
i think ans===25% option (B)correct

ɳ=Tt/Tt+2*Tp

where a=propagation delay/transmission delay
Answer:

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