5,900 views

2 Answers

Best answer
10 votes
10 votes

RAM 2 GB =231 B

Page size = 8 KB = 213 B

Number of Entries in inverted page table = 231 / 213 =218

selected by
2 votes
2 votes

Inverted page table is a global page table maintained by the operating system for all the processes. There is just one page table in the entire system, implying that additional information needs to be stored in the page table to identify page table entries corresponding to each process.

here no of pages are possible  = 231 / 213 =218

 for ex

Answer:

Related questions

8 votes
8 votes
9 answers
1
4 votes
4 votes
6 answers
2
makhdoom ghaya asked May 2, 2016
7,924 views
Which of the following are the likely causes of thrashing?Page size was very small.There are too many users connected to the system.Least recently used policy is used for...
5 votes
5 votes
2 answers
3
makhdoom ghaya asked May 2, 2016
32,994 views
Consider a logical address space of $8$ pages of $1024$ words each, mapped onto a physical memory of $32$ frames. How many bits are there in the physical address and logi...