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Let $P(E)$ denote the probability of the occurrence of event $E$. If $P(A)= 0.5$ and $P(B)=1$ then the values of $P(A|B)$ and $P(B|A)$ respectively are

1. $0.5, 0.25$
2. $0.25, 0.5$
3. $0.5, 1$
4. $1, 0.5$
asked | 627 views

P(A)= 0.5

P(B)=1

Here there is no dependency in event A and B.
So  P(A $\cap$ B) = P(A) * P(B)

P(A/B)= probability of occurrence  of event A when B has already occurred

= P(A $\cap$ B) / P(B)

= (0.5 * 1) /1 = 0.5

P(B/A)= probability of occurrence  of event B when A  has already occurred

= P(B $\cap$ A) / P(A)

= (1 * 0.5) / 0.5 =  1

Ans- C

answered by Veteran (24.7k points)
edited by
HOW U KNOW THERE IS NO DEPENDENCY
@ashutosh , Since there is nothing said about dependency so I assumed both A and B are  independent event.

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