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Prog \ What is the output of the following program?

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7 votes
7 votes 
#include <stdio.h>
void f(char**);
int main()
{
    char *argv[] = { "ab", "cd", "ef", "gh", "ij", "kl" };
    f(argv);
    return 0;
}
void f(char **p)
{
    char *t;
    t = (p += sizeof(int))[-1];
    printf("%s\n", t);
}

(a) ab (b) cd (c) ef (d) gh

In GATE Exam, if not specified What should be size of integer?

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1 Answer

Best answer
6 votes
6 votes

Answer will be D) gh

Here p will initially point to the "ab", 

p += sizeof(int)

This will translate into p = p + 4; // Consider size of int is 4 

Now p will point "ij".

(p)[-1];

will translate into *(p - 1), then it will return the address of "gh", 

//Why address of "gh", because p is double pointer, hence single pointer will return the address its element.

Then t will have the address of "gh". Hence "gh" will be printed. 

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