Starting index = 1.
Starting index address = 1120.
For index = 49
Starting address would be $1120+(49-1)*3$
Why? Because doing $1120+(49)*3$ will give us the "ending address" of A[49] => Starting address of A[50].
So, $1120+(48)*3$ = 1264. Option C
//Think of it as the question asked for the "ending address" of index 48.