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Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data are stores in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk are respectively

  1. 256 Mbyte, 19 bits
  2. 256 Mbute, 28 bits
  3. 512 Mbyte, 20 bits
  4. 64 Gbyte, 28 bits
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A) is the ans

Capacity of the disk = 16 surfaces * 128 tracks * 256 sectors * 512 bytes = 256 Mbytes.
To calculate number of bits required to access a sector, we need to know total number of sectors. Total number of sectors = 16 surfaces * 128 tracks * 256 sectors = 2^19
So the number of bits required to access a sector is 19.

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Capacity of disk= no of surfaces* no of tracks/surface* no of sectors/track* data / sector =16*128*256*512=2^28B=256MB No of bits require to identify sector of particular track of partiular surface =bits to identify surface+bits to identify track+bits to identify sector=4+7+8=19 bits So ans is a
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Number of surfaces =16
Tracks per surface=128
Sectors per track=256
Data which will store per sector=512 bytes
Capacity of the disk = 16 surfaces X 128 tracks X 256 sectors X 512 bytes = 256 Mbytes.
The number of bits required to access a sector =Total number of sectors.
= 16 surfaces X 128 tracks X 256 sectors
=2^4x2^7x2^8=2^19
Answer:

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