cant the answer be like this ::
let an integer m exist in between 0<=m<=9 which is correct . so probability of choosing it would be 1/10 .
probability of choosing any other integer than m would be =9/10
so probability of choosing only wrong integers in 3 chances would be = (9/10)*(9/10)*(9/10)=729/1000
so probability of choosing the right integer would be = 1- 729/1000=271/1000 .
correct me if I am wrong .
Ans.D