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The Boolean expression $(\text{A}+\overline{\text{C}})(\overline{\text{B}} + \overline{\text{C}})$ simplifies to

  1. $\overline{\text{C}} + \text{A} \overline{\text{B}}$
  2. $\overline{\text{C}} (\overline{\text{A}} +\text{B})$
  3. $\overline{\text{B}}\;\overline{\text{C}} + \text{A}\overline{\text{B}}$
  4. None of these
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2 Answers

Best answer
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12 votes

$\implies(A+C')(B'+C')$

$\implies AB'+AC'+B’C'+C'$

$\implies AB'+(A+B’+1)C'$

We Know ( 1+anything =1)

$\implies AB’+C’$

So the required expression is $AB'+C'$ 

Option (A) is correct.

edited by
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F = ( A + C' ).( B' + C' )

F = C' + A.B'         (Using  Destributive Law :(A + C).(B + C) = C + AB

So Option (A) is correct answer
Answer:

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