6 votes 6 votes The value of $x$ at which $y$ is minimum for $y=x^2 -3x +1 $ is $-3/2$ $3/2$ $0$ $-5/4$ Calculus isro2009 calculus maxima-minima + – go_editor asked Jun 15, 2016 edited Dec 8, 2022 by Lakshman Bhaiya go_editor 1.9k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 7 votes 7 votes Ans B) 3/2 y=x2-3x+1 y'=2x-3 y''=2 // So, y has minimum value the value at point (2x-3)=0 or, x=3/2 srestha answered Jun 15, 2016 selected Jun 15, 2016 by LeenSharma srestha comment Share Follow See all 0 reply Please log in or register to add a comment.