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The value of $x$ at which $y$ is minimum for $y=x^2 -3x +1 $ is

  1. -3/2
  2. 3/2
  3. 0
  4. -5/4
asked in Calculus by Veteran (77.3k points)  
edited by | 476 views

1 Answer

+6 votes
Best answer

Ans B) 3/2

y=x2-3x+1

y'=2x-3

y''=2 // So, y has minimum value

the value at point (2x-3)=0

or, x=3/2

 

answered by Veteran (53.8k points)  
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