The value of $x$ at which $y$ is minimum for $y=x^2 -3x +1 $ is
Ans B) 3/2
y=x^{2}-3x+1
y'=2x-3
y''=2 // So, y has minimum value
the value at point (2x-3)=0
or, x=3/2
3308 Points
1884 Points
1656 Points
1640 Points
1396 Points
1272 Points
1162 Points
1048 Points
1010 Points
754 Points
742 Points
510 Points
490 Points
304 Points
248 Points
Gatecse