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The broadcast address for IP network $172.16.0.0$ with subnet mask $255.255.0.0$ is

  1. $172.16.0.255$
  2. $172.16.255.255$
  3. $255.255.255.255$
  4. $172.255.255.255$
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2 Answers

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9 votes
option B seems correct answer.  explanation

Network mask is designed to get network id out of IP,

In this question you have given IP of network directly, but suppose if IP in question would have been like

172.16.15.20  and mask as, 255.255.0.0

then,

1. find network address by performing "logical AND" of IP and network mask as like this

                172.16.15.20

         &&   255.255.0.0

______________________

              172.16.0.0

Number of 1's in mask represents those many bits are reserved for n/w ID
in this case n/w id is 16 bit and host ID is 16 bits.

2.  After getting network IP, put 1 in all host ID bits that will give you broadcast address of that network

   in this example, 172.16.255.255
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Given address is 172.16.0.0 .

Taking AND of IP and subnet mask will give subnet ID.So 172.16.0.0 will be subnet ID.

So if you want calculate broadcast address then all bit of subnet ID in host portion will set to be 1's.

So broadcast address will be 172.16.255.255.
Answer:

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