6 votes 6 votes Three coins are tossed simultaneously. The probability that they will fall two heads and one tail is $5/8$ $1/8$ $2/3$ $3/8$ Probability isro2011 probability + – go_editor asked Jun 23, 2016 edited Dec 8, 2022 by Lakshman Bhaiya go_editor 2.4k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 13 votes 13 votes Ans D) In 3 coins we are getting 2 heads and 1 tail (H,H,T),(H,T,H),(H,H,T) =3! / 2! =3 ways Now, probability =3/23 =3/8 srestha answered Jun 23, 2016 selected Jun 23, 2016 by Arjun srestha comment Share Follow See all 0 reply Please log in or register to add a comment.
5 votes 5 votes Three coins are tossed so number of outcomes=2*2*2=8 We are required to get probability if getting two heads and one tail. Favourable possibilities = HHT , HTH , THH Hence probability of getting two heads and one tail=$\frac{3}{8}$ Hence,Option(d)$\frac{3}{8}$ is the correct choice. LeenSharma answered Jun 23, 2016 LeenSharma comment Share Follow See all 0 reply Please log in or register to add a comment.
3 votes 3 votes these are the possibilities hhh , hht , thh ,hth, tth, htt,tht, ttt so required is 2 head 1 tail i.e- hht ,thh, hth so probability is 3/8 option d stuti1 answered Jun 23, 2016 stuti1 comment Share Follow See 1 comment See all 1 1 comment reply vinay270490 commented Jun 29, 2016 reply Follow Share Good Explanation 1 votes 1 votes Please log in or register to add a comment.
2 votes 2 votes Out of 3 coins we need 2 head and 1 tail P(head)=P(T)=1/2 3C2(1/2)2(1/2)=3/8 is the ans Anjali_aspirant answered Jun 23, 2016 Anjali_aspirant comment Share Follow See all 0 reply Please log in or register to add a comment.