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If the binary search algorithm determines that the scanned argument is in upper half of the array,which of the following statement will set the appropriate variable to the appropriate value.

A) startsub= middlesub-1;

B) startsub=middlesub+1;

C)stopsub=middlesub-1;

D)stopsub=middlesub+1;
asked in DS by (411 points)   | 154 views

2 Answers

+1 vote
Best answer
Option B is Ans

Cz as we know the Searching element is in Upper half then We will Increase the middlesub index  by 1. So that our search space is reduced by half.

So stopsub as it is and startsub=middlesub+1

So option B is correct Ans.
answered by Veteran (16.3k points)  
selected by
For the binary search ,the array is order(ascending).So if we know searching element is in upper half ,means that we should continue search in upper half.So our lower index would change and not the upperindex..

My confusion is with the understanding of the question.what the question mean when it says "Scanned argument".Is it the key that we want to search (search argument) or the scanned array element.

If search argument is less than the middle element the we do stopsub=middle -1;

And if the search argument is greater than middle element then we do startsub=middlesub+1;

Please solve my doubt around the question understanding.
Oh..Yes I have drawn the array vertically ;;So I Thought that Upper half means LHS..

But Now I drawn it horizontally..Cz max people do so.

&Ur Doubt:--It is the search element

 

See my Edited Ans..->>Thanks for Comment
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B. startsub = middlesub + 1
answered by Loyal (3.4k points)  


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