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2 Answers

Best answer
4 votes
4 votes

8 memory chips

each require 12 address lines and 4 data lines

Total size of memory=(8⨉212⨉4)/8 =214B =16KB

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0 votes
0 votes

since 4 data lines .we can have 16 bit in one line. since memory can be byte addressable in general in line we have 2 byte

so one chip size will be = number of address lines*line size

                                   =  2^12*2B= 2^13B

and we have 8 such memory chips 

so total size will be=2^3*2^13B=2^16B=64KB

option d is correct

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