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The minimum Boolean expression for the following circuit is

  1. $\text{AB + AC + BC}$
  2. $\text{A + BC}$
  3. $\text{A + B}$
  4. $\text{A + B + C}$
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2 Answers

Best answer
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A(B+C) + AB + (A+B)C

=AB+AC+AB+AC+BC

=AB+AC+BC 

Hence,Option(A)AB+AC+BC.

edited by
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2 switch a,b in series =a.b

2 switch a,b in parallel=a+b 

so above circuit diagram gives expression A(B+C)+AB+(A+B)C

=AB+AC+AB+AC+BC=AB+AC+BC  Option A is Correct

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