14 votes 14 votes The minimum Boolean expression for the following circuit is $\text{AB + AC + BC}$ $\text{A + BC}$ $\text{A + B}$ $\text{A + B + C}$ Digital Logic isro2016 digital-logic boolean-algebra + – go_editor asked Jul 5, 2016 edited Jan 24 by makhdoom ghaya go_editor 5.4k views answer comment Share Follow See 1 comment See all 1 1 comment reply Hira Thakur commented Jun 13, 2023 reply Follow Share if $a,b$ switches are in series connection then it can be written as $a.b$ if $a,b$ switches are in parallel connection then it can be written as $a+b$ so from the given circuit: $\implies A.(B+C)+A.B+(A+B).C$ $\implies AB+AC+AB+AC+BC$ $\implies AB+BC+AC$ 1 votes 1 votes Please log in or register to add a comment.
Best answer 23 votes 23 votes A(B+C) + AB + (A+B)C =AB+AC+AB+AC+BC =AB+AC+BC Hence,Option(A)AB+AC+BC. LeenSharma answered Jul 5, 2016 edited Nov 3, 2017 by LeenSharma LeenSharma comment Share Follow See all 2 Comments See all 2 2 Comments reply Siva Tarun commented Aug 3, 2017 reply Follow Share Hi how you are determining whether (a+b) or ab. can you please provide me a source to learn this concept. Bit confusing, confused during my b.tech too :-P 0 votes 0 votes srivivek95 commented Nov 3, 2017 reply Follow Share @LeenSharma In the lowest portion of the circuit diagram AB should be (A+B) & AB+C should be (A+B)C 0 votes 0 votes Please log in or register to add a comment.
7 votes 7 votes 2 switch a,b in series =a.b 2 switch a,b in parallel=a+b so above circuit diagram gives expression A(B+C)+AB+(A+B)C =AB+AC+AB+AC+BC=AB+AC+BC Option A is Correct Sanjay Sharma answered Jul 5, 2016 edited Jul 5, 2016 by Sanjay Sharma Sanjay Sharma comment Share Follow See 1 comment See all 1 1 comment reply shekhar chauhan commented Jul 5, 2016 reply Follow Share please correct the word gives 0 votes 0 votes Please log in or register to add a comment.