Find probability that on a 1024-host network, two addresses will be the same

Question

Suppose Ethernet physical addresses are chosen at random (using true random bits). The probability that on a 1024-host network, two addresses will be the same is : 

• A. 1.77 × 10–9
• B. 1.87 × 10–9
• C. 1.99 × 10–9
• D. 1.98 × 10–8

Comments

You can provide a good and descriptive solution !! Even if answer is correct .

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@kapilp i'll do but i have some dout first i need to check it...

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hi,can you pls explain this a little more??

Answer 1

should'nt the answer be :

(1/ 2^48) * 1024 C₂ as question is asking that two have same IP adrress,then for a host to have same ip address then P = 1 / 2⁴⁸

and as no. of hosts = 1024,so these two hosts can be chosen by 1024 C_2....

please help in this one.