for E2:
FIND WHICH ONE IS LARGE
N^3*2^N=6N^2*3^N
N*2^N=6*3^N(NOW TAKE LOG ON BOTH SIDE)
LOG(N*2^N)=LOG(6*3^N)
LOG N +N LOG 2 =LOG 6 +N LOG 3
LOG N+ N = 1.5 N( LOG6=CONSTANT,,,LOG3=1.5)
LOG N =0.5N
O(0.5N)=O(6*N^2*3^N)
SO E2 IS FALSE
FOR E1:
COMPARE N^E=logn
since E>0 N^E is large compared to logn
so E1 IS CORRECT
OPTION B...........E1 IS CORRECT AND E2 IS NOT CORRECT