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One dice is thrown three times and the sum of the thrown numbers is 15.find the probability for which number 4 appears in first throw.
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Total no of patterns where 15 as sum appears...

366,456,465,546,564,555,645,654,663,636

So probability = 2/10 = 1/5

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ans = P( number in 1st dice throw is 4 & sum of numbers in 2nd and 3rd dice throw is 11 ) / P(number in 1st dice throw is 4)

= (1/6 * 2/36 ) / ( 1/6 )

=1/18

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