2 votes 2 votes Consider a disk with 16384 bytes per track having a rotation time of 16 msec and average seek time of 40 msec. What is the time in msec to read a block of 1024 bytes from this disk? 57 msec 49 msec 48 msec 17 msec Operating System ugcnetcse-dec2015-paper2 operating-system disk + – go_editor asked Aug 8, 2016 retagged Nov 13, 2017 by Arjun go_editor 4.8k views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply Manoj Kumar Pandey 1 commented Jun 13, 2018 reply Follow Share Why rotational latency is divided by 2? 0 votes 0 votes Rackson commented Oct 5, 2018 reply Follow Share because its calculate average rotational latency 0 votes 0 votes Please log in or register to add a comment.
4 votes 4 votes Transfer time = ((1024 bytes *16 ms)/ (16384 bytes )) = 1 msec Rotational letency = 16 msec / 2 = 8 msec total time = seek + rotational letency + transfer time = 40 + 8 + 1 = 49 msec B is answer Prashant. answered Aug 8, 2016 Prashant. comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments brijeshnayyar75 commented Nov 15, 2018 reply Follow Share Because for calculating average rotational latency we have to divide by 2 0 votes 0 votes deenanathgupta commented Dec 3, 2019 reply Follow Share Rotation letancy ??? 0 votes 0 votes swami_9 commented Jul 11, 2021 reply Follow Share i have not understood the transfer time calculation. can anyone explain. 0 votes 0 votes Please log in or register to add a comment.