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$\textstyle \lim_{x \to 2}\frac{(x-2)}{log(x-1)}$                      $\frac{0}{0} form$                      

Apply L Hospital's rule

$\textstyle \lim_{x \to 2}\frac{(1)}{\frac{1}{x-1} \times 1}$

$\textstyle \lim_{x \to 2}(x-1)$

$2-1$

$=1$
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