What is the output of the program?

Question

# include <stdio.h>
int main()
{
static int a[ ] ={90, 98, 99, 96, 84, 70};
static int *p[ ]={a+2, a+1, a, a+3, a+4, a+5};
static int **S={p+4, p+5, p+1, p, p+2, p+3};
int *** ptr; ptr=S+2;
printf(“%d”, ***(ptr+3)-**(p+1));
}

Comments

-2 should be ans...

Answer 1

Here there is a typo **S Should be array

It should be **S[ ]-2 is Ans

Comments

here p and s both are double pointer. Both have same useage, right?

what is the use of using static int to array or pointers here?

Only int a[ ] , int *p[ ] ,or int **S can give here same output. Am I right?

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Thanks for Ur Comment  Respected @srestha

There is a typo in this question.

**S should be array means **S[ ].

 

Yes U r abs  Right...@srestha

Here Static has no significance if we remove it also it will give same result.

Bcz Static has local Scope like auto only and Here lifetime has no importance.

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No, static has a usage here. Many people seeing it will leave the question unanswered :)

Actually in no C program any variable being declared static in main is not useful. Because

1. Calling main from a C program is undefined behaviour.
2. Scope of a variable defnied inside main (or any function) is inside main only.

Usually we declare a variable static to

1. ensure it has a live memory (lifetime) until program ends execution. Useful for preserving values across function calls.
2. to restrict a global variable scope to within the compilation unit. This allows the same variable name to be used in a different compilation unit as global and then all the units can be linked together to make the executable.