Is this can be an easy method?
P(A)=Insufficient s/w=0.65, P(A')=Sufficient s/w=0.35
P(B)=Insufficient h/w=0.45, P(A')=Sufficient h/w=0.55
P(A U B)=0.7
Now, we want Sufficient s/w and Sufficient h/w= P(A' intersection B')=P(A U B)'=(0.7)'=1-0.7=0.3
Final answer=P(A' intersection B')/P(A')=0.3/0.35