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In this question, After fragmenting at Network2, what will be the total length field values of the 4 fragmented IP packets ?

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SInce sender Payload size=1600;

MTU of first network=1500Byte

No. Of fragments=1600/1480=1.089=~2

First fragment=1480(Payload)+20(Header)

Second fragment=120(payload)+20(Header)

------------------------------------------------------------------------------

Now In second case::

MTU=480

Number of fragment=1480/460=~4

So

first fragment=456 +20,4560+20,4560+20,112+20

Total=4

-------------------------------------------------

Total Data received by B=1700Byte

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