Digital logic

Question

A number N is stored in a 4-bit 2's complement form as
     A3 A2 A1 A0
It is copied into a 6-bit register and after a few operations,the final bit pattern is
A3 A3 A2 A1 A0 A1
The value of this bit pattern in 2's complement form is given in terms of original number N as
A) 32A3 +2N +1
B) 32A3 -2N -1
C) 2N -1
D) 2N +1

Answer 1

Answer is D
Stored 2's compliment number is b_n-1+b_n-2+_____b₁+b₀

Its magnitude is [-2^n-1b_n-1 + 2^n-2b_n-2 +______2b₁+b₀]

Answer 2

option b

Comments

Explain?

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i think some typo in options.

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What you are getting answer sir?

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a3a3a2a1a0a1 =  2^5*a3 + a3a2a1a00+ a1 = 32a3 + 2(a3a2aa1a0) + a1

in terms of complement getting none.