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11 votes
11 votes
In the bitmap approach " every disk block will map with one binary bit (not matter it is free or not)"
total no of disk blocks=disk size/one disk block size = 80GB/8KB =10M
now one disk block contains 64 K bits so it contains info (free /busy) about 64K disk blocks.
so for 1 M blocks = 10M/64K=160 disk blocks.{--ans}
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7 votes
7 votes
in bit map each block is represented by a single bit 0/1.

so total no. of blocks = 80GB/8KB

                                   = 10M blocks

block size = 8KB hence

it can contain information of  8K*8bit =64K blocks

so required blocks are = 10M / 64K

                                     = 160 blocks

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