1 votes 1 votes exp=(A'B+AC)' ? , I tried consensus theorem and obtained (AC+A'B+CB)' Alex Louis asked Sep 21, 2016 Alex Louis 341 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 0 votes 0 votes GIVEN EXPRESSION : (A'B+A'C)' =(A+B')(A'+C') =AA'+AC'+B'A'+B'C' =0+AC+B'A'+B'C' Now by consensus remove B'C' =AC'+B'A' ( final ans) focus _GATE answered Sep 21, 2016 edited Sep 21, 2016 by focus _GATE focus _GATE comment Share Follow See all 4 Comments See all 4 4 Comments reply Alex Louis commented Sep 21, 2016 reply Follow Share can you please tell that how you obtain the first step = (A+B')(A'+C') 0 votes 0 votes Pankaj kumar commented Sep 21, 2016 reply Follow Share by using demorgan's theorem. 0 votes 0 votes Pankaj kumar commented Sep 21, 2016 reply Follow Share It is AA' not AA 0 votes 0 votes focus _GATE commented Sep 21, 2016 reply Follow Share Yes, now done :) 0 votes 0 votes Please log in or register to add a comment.