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exp=(A'B+AC)' ? , I tried consensus theorem and obtained (AC+A'B+CB)'

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GIVEN EXPRESSION : (A'B+A'C)'

=(A+B')(A'+C')

=AA'+AC'+B'A'+B'C'

=0+AC+B'A'+B'C'

 Now by consensus remove B'C'

=AC'+B'A' ( final ans)
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