3 votes 3 votes Suppose transmission rate of a channel is $32$ kbps. If there are $‘8’$ routes from source to destination and each packet $p$ contains $8000$ bits. Total end to end delay in sending packet $P$ is _____. $2$ sec $3$ sec $4$ se $1$ sec Computer Networks ugcnetcse-aug2016-paper3 computer-networks network-switching + – makhdoom ghaya asked Oct 1, 2016 recategorized Oct 14, 2018 by Pooja Khatri makhdoom ghaya 2.9k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
3 votes 3 votes Answer is A time = (data*routes) / speed Ishani Raval answered Jan 19, 2017 Ishani Raval comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Since there are 8 routes we can send 8 packets (8*8000 bits) simultaneously Total end to end delay= Transmission time = 8*8000/ 32*1000 = 2 sec sh!va answered Mar 8, 2017 sh!va comment Share Follow See 1 comment See all 1 1 comment reply Satya narayana commented Oct 9, 2018 reply Follow Share The question is "Total end to end delay in sending packet P is" ? Why are we calculating for 8 packets or why are we considering other 7 routes for packet P in transmission time? If we are supposed to send packets in all routes then its correct. But they asked only for packet P. 0 votes 0 votes Please log in or register to add a comment.