The frame transmission time is 200/200 kbps or 1 ms. a. If the system creates creates 1000 frames per second, this is 1 frame per millisecond. The load is 1. In this case S = G× e−G S = G× e or S = 0 368 (36 8 percent) This means G or S = 0.368 (36.8 percent). This means that the throughput is 1000 × 0.0368 = 368 frames. Only 386 frames out of 1000 will probably survive