thanks for the above solution..
can we solve this using recursion?
like i was solving like this but could 'nt proced further-
a_{n+1 }= 2(a_{n} - 3)
so,a_{n} =( a_{n+1}/2) + 3
a_{n+1 }= (a_{n+2}/2) + 3 putting this in a_{n},we get a_{n }= (a_{n+2 }/ 2^{2}) + 3/2 + 3
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solving o..we get
a_{n} = a_{ n + k }/2^{k } + 3( 1+ 1/2 + 1/2^{2} + ....... + 1/ 2^{k-1})
now,i dun know how to solve further
i was taking base condition as a_{10} = 14..but i did nt lead me anywhere..can u pls help