thanks for the above solution..
can we solve this using recursion?
like i was solving like this but could 'nt proced further-
an+1 = 2(an - 3)
so,an =( an+1/2) + 3
an+1 = (an+2/2) + 3 putting this in an,we get an = (an+2 / 22) + 3/2 + 3
solving o..we get
an = a n + k /2k + 3( 1+ 1/2 + 1/22 + ....... + 1/ 2k-1)
now,i dun know how to solve further
i was taking base condition as a10 = 14..but i did nt lead me anywhere..can u pls help