There are many variations of Quicksort. We may choose the pivot for each partition step in various ways. There are various strategies for partitioning an array segment into one subpartition of consecutive array positions that has values less than or equal to the pivot and another subpartition of consecutive array positions with those values greater than the pivot. The recursion that partitions the array into smaller and smaller segments may be stopped in various ways. However, even with all that variation, not any set of values can ever be a partition at any level. Your problem is to consider the Quicksorting of an array that initially has the values 3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5, 8, 9, 7 and identify below the one set of values that could possibly be one entire partition at some level of the Quicksort recursion

a) 6, 9, 7, 8, 9

b) 3, 1, 3, 1

c) 5, 4, 3, 3, 5

d) 1, 4, 1, 3