1 votes 1 votes richa07 asked Nov 18, 2016 richa07 343 views answer comment Share Follow See 1 comment See all 1 1 comment reply saurabh rai commented Nov 18, 2016 reply Follow Share RAW dependency(2) I2-I4 I2-I5 WAW dependency(2) I1-I2 I2-I5 WAR dependency(3) I2-I3 I4-I5 I3-I4 m i right ?? 0 votes 0 votes Please log in or register to add a comment.
Best answer 2 votes 2 votes RAW:True dependency we also called it as dirty read. 1. I2 to I4 2. I2 to I5 WAR:is anti-dependency. 3. I2 to I3 , 4.I2 to I4, 5. I3 to I4, 6. I4 to I5 WAW: Write after Write 7. I1 to I2 8. I2 to I5 so ANS should be :8 papesh answered Nov 18, 2016 selected Nov 18, 2016 by Kapil papesh comment Share Follow See all 3 Comments See all 3 3 Comments reply saurabh rai commented Nov 18, 2016 reply Follow Share @gabbar i think there should b no WAR dependency between (I2-I4) it will b eliminated by (I3-I4) Bcoz of common reg R4 0 votes 0 votes papesh commented Nov 18, 2016 reply Follow Share It is just reading value not updating so we should inlcude it. 1 votes 1 votes saurabh rai commented Nov 18, 2016 reply Follow Share Thnx :) I WAS WRONG......... 0 votes 0 votes Please log in or register to add a comment.