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+1 vote

Can you please check if the following solution is correct? if not please correct it.


asked in Calculus by Veteran (11.7k points)   | 112 views
Yes ur solution is fine @Vijay Thakur...@kunal chalotra at x = -3 , absolute maximum exists not local maxima exists..

@habib khan
what should be the answer of this question according you (B) or (D)

after calculating critical points we have differentiate second time to check local maxima and minima .rt habib??
Yes then we have 0 at x = 1 and > 0 at x = 0 ..So clearly x = 0 is a point of minima..But for x = 1 , we need to check further..
It should be  B) without any doubt as in case of local minima or maxima we do not consider the extreme points or points of discontinuity..

Only we check the points using derivatives..That is it..

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