All options are wrong.
Answer=^6-8*24
First we convert given Postfix to Infix: Scan the i/p from L to R
push 6,push 8,push 2,push 4
Then pop 2 and 4 and push (2*4) onto stack.
Then pop (2*4) and 8 and push (8-(2*4)) onto stack.
Then pop 6 and (8-(2*4)) to get 6^(8-(2*4)) i.e 1
Now convert this infix to prefix:
=^6-8*24
Cross Check whether this prefix evaluates to 1 using PREFIX Evaluation method : scanning input from Right to Left
In prefix evaluation stack top becomes left operand of operator not the right operand ******.
push 4,push 2
pop 2,4 push (2*4)
push 8
pop 8,(2*4),push (8-(2*4))
push 6
pop last 2 stack contents =====> 6^(8-(2*4)) i.e 1
Hence our prefix is correct.