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Suppose host A sends a message to some byte (say $x$) to host B. But in between routers fragment the packet sent by A and as a result 5 fragments reach destination. (IP header = $20B$). What is the IP overhead at destination??

Somewhere I read $1$ IP header is included in host message, but $5$ IP header's reach destination. So IP overhead at destination is equal to size of $4$ IP headers i.e., 4*20 = 80B

But discussing with my friend's in college they say IP header is also an overhead. So total Overhead is equal to size of $5$ IP headers.

Please clarify what is wrong what is right??

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Yes . according to me also IP header is overhead . coz we are intereseted in sending the data as much as possible in a go . but due to MTU (maximum transmission unit) we have take care of data limits or size of packet . In which we have to consider the size of IP header also .
 so if packet is fragmented in to 5 packets so total IP overhead at destination is 5 IP header .

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