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1 Answer

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L = {ba,baa,baaa,....ab,aab,aaab,.....aba,abaa,abaaa....,aabaa,aaabaaa.......}

but we have only ab or ba as a inverse function of h.

h-1(L)=h-1({ba,ab, and all other will give empty set})=0 and 1 

as h-1(ab)=0 and h-1(ba)=1

So Answer is C.