Consider the Venn diagram above..In light of the given question we can say ,
n(A U B U C) = n(A) U n(B) U n(C) - n(A ∩ B) - n(B ∩ C) - n(A ∩ C) + n(A ∩ B ∩ C)
==> n(A ∩ B) + n(B ∩ C) + n(A ∩ C) = n(A) U n(B) U n(C) - n(A U B U C) + n(A ∩ B ∩ C)
==> n(A ∩ B) + n(B ∩ C) + n(A ∩ C) = 48 - 34 + 3
==> n(A ∩ B) + n(B ∩ C) + n(A ∩ C) = 17
==> y + s + p + 3r = 17 [According Venn diagram]
==> y + s + p = 17 - 3 * 3 = 8
==> n(exactly 2 awards received) = 8 ...............(1)
Now again using Venn diagram we have :
x + z + t + y + s + p + r = 34 (n(A U B U C)
==> x + z + t + 8 + 3 = 34
==> x + z + t = 34 - 11
==> n(exactly 1 award received) = 23