please give the answer for the below question

Question

consider a system where each file is associated with a 16 bit number.for each file ,each user should have the read and write capability.how much memory is needed to store each user's access data?

A) 16KB                B) 32KB                C) 64KB              D) 128KB

Comments

i think this question is incomplete.??

Answer 1

D. no of file = 2^16. total bits required for access information = 2 one for read and one for write.
per user memory required= 2^16*2 = 128KB

Comments

1 bit for read and 1 bit for write so 2 bit. or there r 4 cases. read access and write acess , no read but write ....

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I feel it wrong. The way they have done it is.calculated memory first. But memory = no of files * 16 bit.( if 16 bit are not used for addressing + no relation between file and memory given) number of file is not given which means it is given to say that from 16 bit we can address every possible file.

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yes...@tendua