471 views
0 votes
0 votes
Which of the following statements is incorrect
i) In a graph G with number of vertices n, n ≥ 2, there are two vertices that have exactly the same degree
ii) Let G be a K-regular bipartite graph with k ≥ 2. Then G has no cut edge

1 Answer

0 votes
0 votes
1. nothng is mentioned about the type of graph , so can't comment accurately, otherwise considering the Simple Graph the statment is True that atleast 2 vertex must have same degree (Havell-Hakimi theorem).

2. Statment True: because as k>=2 there cant be any edge whose removal disconnect as every vertex has same degree and being bipartite 2 sets willalways be connected even though 1 edge is removed

Related questions

1 votes
1 votes
1 answer
1
0 votes
0 votes
1 answer
2
gagan55 asked Jun 30, 2023
190 views
Number of hamiltonian cycles for a graph K 5, 5( bipartite graph ) ??
0 votes
0 votes
1 answer
3
Dhiraj_777 asked May 4, 2023
516 views
In a Connected Planar Bipartite Graph of order 10 atmost how many edges be present ?
0 votes
0 votes
1 answer
4
Sahil_Lather asked Apr 15, 2023
474 views
Graph G is obtained by adding vertex s to $K_{3,4}$ and making s adjacent to every vertex of $K_{3,4}$ .The find the minimum number of colours required ot edge-colour is ...