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+5 votes
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Please explain how to solve this.

asked in DS by Boss (6.2k points)   | 113 views

2 Answers

+4 votes
Best answer

Correct me if i am wrong

answered by Active (1.2k points)  
selected by
Thanx nicely explained..:)
If the question was for column major then what will be the address.....???

I got 1046.....is it right...??
0 votes

If we take the size of each element as 1 bytes. 

Then its actually asking for the address of A[4][2] in the lower triangular matrix.

In Row Major Order, A[i][j] = Base + Size( (i - lower1) *NNS + (j-lower2) )     //NNS = Natural No.Sum.

So, A[4][2] = 1000 + 1 ( ( 4-(-6) )*NNS + (2-(-6) ) )

                  = 1000 + (1+2+3+4+5+6+7+8+9+10) + 8

                  = 1000 + 55 + 8

                  = 1063

answered by Junior (517 points)  


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